TY - JOUR
T1 - A duality theorem on a pair of simultaneous functional equations
AU - Mertens, Jean François
AU - Zamir, Shmuel
PY - 1977/9
Y1 - 1977/9
N2 - Given P and Q convex compact sets in RkandRs, respectively, and u a continuous real valued function on P × Q, we consider the following pair of dual problems: Problem I-Minimize f{hook} so that f{hook}: P × Q → R and f{hook} ≥ CavpVexq × max(u, f{hook}). Problem II-Maximize g so that g: P × Q → R and g ≤ Vexq × Cavpmin(u, g). Here Cavp is the operation of concavification of a function with respect to the variable p ε{lunate} P (for each fixed q ε{lunate} Q). Similarly, Vexq is the operation of convexification with respect to q ε{lunate} Q. Maximum and minimum are taken here in the partial ordering of pointwise comparison: f{hook} ≤ g means f{hook}(p, q) ≤ g(p, q) ∀(p, q) ε{lunate} P × Q. It is proved here that both problems have the same solution which is also the unique simultaneous solution of the following pair of functional equations: (i) f{hook} = Vexqmax(u, f{hook}). (ii) f{hook} = Cavpmin(u, f{hook}). The problem arises in game theory, but the proof here is purely analytical and makes no use of game-theoretical concepts.
AB - Given P and Q convex compact sets in RkandRs, respectively, and u a continuous real valued function on P × Q, we consider the following pair of dual problems: Problem I-Minimize f{hook} so that f{hook}: P × Q → R and f{hook} ≥ CavpVexq × max(u, f{hook}). Problem II-Maximize g so that g: P × Q → R and g ≤ Vexq × Cavpmin(u, g). Here Cavp is the operation of concavification of a function with respect to the variable p ε{lunate} P (for each fixed q ε{lunate} Q). Similarly, Vexq is the operation of convexification with respect to q ε{lunate} Q. Maximum and minimum are taken here in the partial ordering of pointwise comparison: f{hook} ≤ g means f{hook}(p, q) ≤ g(p, q) ∀(p, q) ε{lunate} P × Q. It is proved here that both problems have the same solution which is also the unique simultaneous solution of the following pair of functional equations: (i) f{hook} = Vexqmax(u, f{hook}). (ii) f{hook} = Cavpmin(u, f{hook}). The problem arises in game theory, but the proof here is purely analytical and makes no use of game-theoretical concepts.
UR - http://www.scopus.com/inward/record.url?scp=0000457303&partnerID=8YFLogxK
U2 - 10.1016/0022-247X(77)90041-5
DO - 10.1016/0022-247X(77)90041-5
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AN - SCOPUS:0000457303
SN - 0022-247X
VL - 60
SP - 550
EP - 558
JO - Journal of Mathematical Analysis and Applications
JF - Journal of Mathematical Analysis and Applications
IS - 2
ER -