Abstract
We give a combinatorial equivalent to the existence of a non-free hereditarily separable group of cardinality א1. This can be used, together with a known combinatorial equivalent of the existence of a non-free Whitehead group, to prove that it is consistent that every Whitehead group is free but not every hereditarily separable group is free. We also show that the fact that ℤ is a p.i.d. with infinitely many primes is essential for this result.
Original language | English |
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Pages (from-to) | 213-235 |
Number of pages | 23 |
Journal | Israel Journal of Mathematics |
Volume | 88 |
Issue number | 1-3 |
DOIs | |
State | Published - Oct 1994 |