Abstract
A crystal structure determination for bi-4 H-cyclopenta[def]-phenanthren-4-ylidene, 1, reveals a molecular conformation rather like that reported earlier for bifluorenylidene, 2. However, unexpectedly, the twist angle about the ethylenic linkage is substantially smaller in 1 (average values are 30.8 and 40.7°, respectively). Comparison of bonding geometry, combined with the results of molecular mechanics calculations for 1, demonstrates that syn pyramidalization can play an important role in determining a stable conformation for overcrowded, twisted aromatic enes. The average out-of-plane bending angles for the ethylenic carbon atoms of 1 and 2 are 8.6 and 4.4°, respectively.
| Original language | English |
|---|---|
| Pages (from-to) | 123-126 |
| Number of pages | 4 |
| Journal | Structural Chemistry |
| Volume | 1 |
| Issue number | 1 |
| DOIs | |
| State | Published - Jan 1990 |
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