Abstract
In this work we will prove the following:Theorem 1. cons(ZF) implies cons(Z.FC+ there exists a Q-set of reals + there exists a set of reals of cardinality N, which is not Lebesgue measurable). Theorem 2. cons(ZF) implies cons(ZFC + 20is arbitrarily larger than H2+ there exists a Sierpinski set of cardinality 20) +there are no rapid filters on a). These theorems give answers to questions of Fleissner[Fl] and Judah [Ju].
| Original language | English |
|---|---|
| Pages (from-to) | 821-832 |
| Number of pages | 12 |
| Journal | Proceedings of the American Mathematical Society |
| Volume | 111 |
| Issue number | 3 |
| DOIs | |
| State | Published - Mar 1991 |
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